Now that we have an understanding of how to find the limiting reagent lets try a few practice problems. Here we go:
1.For the balanced equation shown below, what would be the limiting reagent if 46.3 grams of C3H6O were reacted with 73.2 grams of O2?
C3H6O+4O2=>3CO2+3H2O
C3H6O O2
2.For the balanced equation shown below, what would be the limiting reagent if 11.5 grams of C6H6O3 were reacted with 6.57 grams of O2?
C6H6O3+3O2=>6CO+3H2O
C6H6 O2
3.For the balanced equation shown below, what would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of O2?
C2H3OF+2O2=>2CO2+H2O+HF
C2H3OF O2
4.For the balanced equation shown below, what would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of O2?
4C3H9N+25O2=>12CO2+18H2O+4NO2
C3H9N O2
5.For the balanced equation shown below, what would be the limiting reagent if 19.2 grams of C7H16 were reacted with 120 grams of O2?
C7H16+11O2=>7CO2+8H2O
C7H16 O2